2w^2-3w-230=0

Solution for 2w^2-3w-230=0 equation:

2w^2-3w-230=0

a = 2; b = -3; c = -230;
Δ = b2-4ac
Δ = -32-4·2·(-230)
Δ = 1849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1849}=43$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-43}{2*2}=\frac{-40}{4}
=-10
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+43}{2*2}=\frac{46}{4}
=11+1/2
$